Answer to Question #110015 in Optics for Nya

Question #110015

A concave mirror has a focal length of 0.25 m. If an object produces a virtual image 0.04 m from the mirror, where is it located?

Expert's answer

using mirror's formula

"\\frac1f=\\frac1u+\\frac1v"

"\\frac{1}{-0.25}=\\frac1u+\\frac1{0.04}\\\\\\frac1u=-29"

"u=-\\frac{1}{29}m"

u=-0.034 m

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