The magnetic force acting on the conductor
"F=I\\cdot B\\cdot l\\cdot\\sin \\alpha"
Assume that "l=1 m" and "\\alpha=30\u00b0". So
"F=I\\cdot B\\cdot l\\cdot\\sin \\alpha=3.5\\cdot 0.1\\cdot 1\\cdot \\sin30\u00b0=0.175 N"
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