Given,
Thickness of the soap bubble "(t)=125nm = 125\\times 10^{-9}m"
Refractive index of water "(\\mu)=1.33"
We know that the longest wavelength for the constructive wavelength
"\\Rightarrow2\\mu t = (n-\\frac{1}{2})\\lambda"
Now, substituting the values,
"\\Rightarrow \\lambda = \\frac{2 \\mu t}{(n-\\frac{1}{2})}"
"\\Rightarrow \\lambda = \\frac{2\\times 1.33 \\times 125\\times 10^{-9}m}{\\frac{1}{2}}"
"\\Rightarrow \\lambda = 4\\times 1.33\\times 125\\times 10^{-9}m"
"\\Rightarrow \\lambda = 0.665\\mu m"
Comments
Leave a comment