Answer to Question #153688 in Optics for mavis

Question

an object is placed at 0.6 m from a convex lens of focal length 0.15m . Calculate the position and nature of image.

Answer 1

We know from lens formula $\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$ where f - focal length = 0.15m = 15cm,

u = object distance = −0.6m = −60cm and v = image distance

Thus putting the above values in the equation we get,

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$ = $\frac{1}{10} - \frac{1}{6} = \frac{3 - 5}{30} = \frac{-2}{30} => v = -15cm$

m = $\frac{v}{u}$ = $\frac{-15cm}{-60cm} = \frac{1}{4}$