Answer to Question #159503 in Optics for shalize

Question #159503

Two physics students are separated 6.80 m and are creating a standing wave interference pattern along a slinky consisting of 5 loops. If the students are vibrating their ends of the slinky with a frequency of 3.10 Hz, calculate the speed of the wave energy.


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Expert's answer
2021-01-29T04:29:25-0500
L=12nλ=52λ=2.5λ.L=\dfrac{1}{2}n\lambda=\dfrac{5}{2}\lambda=2.5\lambda.

From this formula we can find the wavelength of the wave travelling in the slinky:


λ=L2.5=6.8 m2.5=2.72 m.\lambda=\dfrac{L}{2.5}=\dfrac{6.8\ m}{2.5}=2.72\ m.

Finally, we can find the speed of the wave from the wave speed formula:


v=fλ=3.1 Hz2.72 m=8.43 ms.v=f\lambda=3.1\ Hz\cdot2.72\ m=8.43\ \dfrac{m}{s}.

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