Answer to Question #337264 in Optics for chan

Question

Suppose a layer of oil (refractive index is 1.45) floats on water (refractive index is 1.33).If a ray of light shines onto the oil with an incidence angle of 40°, what is the angle formes between the ray and the surface of the water?

a) Given;

b)Formula:

c)Solution

d)Final answer with unit:

Answer 1

$\alpha=90°-40°=50°,$

$\frac{\sin\alpha}{\sin\beta}=n_1,$

$\beta=31.9°,$

$\beta'=90°-\beta=58.1°.$