Answer to Question #348009 in Optics for INGA

Question #348009

If the density of water is 1,00 g/cm³ and atmospheric pressure is 1,013 × 10⁵ Pa, the depth in water (in m) where the absolute pressure is four times atmospheric pressure, is equal to

Expert's answer

"\\frac{\\rho gh}p+1=4,"

"h=\\frac{3p}{\\rho g}=31~m."

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