1 Obtain the conditions for observing maxima and minima in a Young two-slit interference pattern.
Let S1 and S2 be two slits separated by a distance d. Consider a point P on XY plane such that CP = x. The nature of interference between two waves reaching point P depends on the path difference S2P-S1P.
We using figure:
"S1P^2=D^2+(x-\\frac{d}{2})^2 (1)""S2P^2=D^2+(x+\\frac{d}{2})^2 (2)"
We get using (1) and (2):
"(S2P - S1P)= \\frac{2xd}{ S2P + S1P } (4)"
for x, d<<< D , S1P+S2P =2D with negligible error included , path difference would be
Phase difference between wave for constructive interference is equal to
In this case, we can write
where
"n=0, \\pm1, \\pm2, \\pm3, ..."Phase difference between wave for destructive interference is equal to
Similarly, for destructive interference,
2 Show that these conditions change when a thin transparent sheet of thickness t and refractive index μ is introduced in the path of one of the superposing beams.
Let a thin transparent sheet of thickness t and refractive index μ be introduced in the path of wave from one slit S1. It is seen from the figure that light reaching the point P from source S1 has to traverse a distance t in the sheet and a distance (S1P−t) in the air. If c and v are velocities of light in air and in transparent sheet respectively, then the time taken by light to reach from S1 to P is given by
The effective path difference at any point P on the screen
Using (5) and (9) we can write for constructive interference
for destructive interference
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