1. The total capacitance C of series connection is given as follows:
C1=2×10−6F1+5×10−6F1+10×10−6F1C=1.25×10−6F The total charge:
Q=CV=1.25×10−6F⋅12V=15×10−6C
2. The total capacitance of parallel connection:
C=2×10−6F+5×10−6F+10×10−6F=17×10−6F The voltage:
V=CQ=17×10−6F50×10−6C≈2.9V
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