Answer to Question #334511 in Physics for Alemayehu kumsa

Question #334511

A projectile is fired in such away that its horizontal range is equal to its maximum height what is the angle of projection ?

1
Expert's answer
2022-04-28T16:42:32-0400
Hmax=LmaxH_{max}=L_{max}

v02sin2θ2g=v02sin2θg\frac{v_0^2\sin^2\theta}{2g}=\frac{v_0^2\sin2\theta}{g}

tanθ=4\tan\theta=4

θ=76\theta=76^\circ


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