Answer to Question #335613 in Physics for Britz3

Question #335613

The force between two electrical charges is 0.4 N. What would be the force if the charges are doubled, and the distance between them increased by 100%? 


1
Expert's answer
2022-05-02T13:43:14-0400
F=kq1q2r2F=k\frac{q_1q_2}{r^2}

F=k2q12q2(2r)2=kq1q2r2=F=0.4NF'=k\frac{2q_1*2q_2}{(2r)^2}=k\frac{q_1q_2}{r^2}=F=0.4\:\rm N


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