Answer to Question #348340 in Physics for gelay

Question

A stone is tossed straight upwards from a height of 2 meters with an initial positive velocity

of 30 m/s. If time it takes to hit the ground is 10 seconds, what is the maximum height it

reaches from the ground?

Answer 1

$$h=\frac{v_0^2}{2g}=\frac{30^2}{2*10}=45\:\rm m$$

$$h_{\max}=h+h_0=45+2=47\:\rm m$$