Answer to Question #349608 in Physics for kate

Question #349608

A ball (m = 0.1 kg) is thrown upwards with a velocity of 8 m/s. At what height will its velocity be 3 m/s?

Expert's answer

"h=\\frac{v^2-v_0^2}{2a}\\\\\n=\\rm\\frac{(3\\: m\/s)^2-(8\\: m\/s)^2}{2*(-9.8\\: m\/s^2)}=2.8\\:\\rm m"

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