Answer to Question #350277 in Physics for jhay

Question

Two stones are thrown vertically upward from the ground, one with three times the initial speed of the other. (a) If the faster stone takes 10 s to return on the ground, how long will it take the slower stone to return? (b) If the slower stone reaches a maximum height of H, how high (in terms of H) will the faster stone go? Assume the two stones are freely falling objects. 

Answer 1

(a)

$$t=2\frac{v_0}{g}$$

Hence

$$t_2=3t_1=3*10\:\rm s=30\: s$$

(b)

$$H=\frac{v_0^2}{2g}$$

Hence

$$H_2=9H_1=9H$$