Simultaneous eigenbasis can be shared only by pairwise commuting collections of operators. Since, in Heisenberg's picture, we have
"\\frac{d}{dt} L_z = \\frac{i}{\\hbar} \\left[ H , L_z \\right] = 0 \\, ,"we observe that "H" and "L_z" commute and, therefore, share simultaneous eigenbasis. On the other hand, "L_z" and "L_x" do not commute, "\\left[ L_z , L_x \\right] = i L_y", so they cannot share simultaneous eigenbasis. Thus, there is only one correct answer to this question.
Answer: "H , L_z" share simultaneous eigenbasis.
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