Answer to Question #340586 in C for Ayane

Question

5. Search and Rescue

by CodeChum Admin

Make a program that will accept an integer and loop for the same number of times as that of the inputted integer and input random integers and add it to the array/list one by one, per line. Afterwards, make your program accept another random integer.

Using that final integer, compare from your array/list if the final integer's value is also present in your current array/list. If so, print "Present"; otherwise, print "None".

Start coding now!

Input

1. Size of the array

2. Elements of the array

3. Integer to be searched

Output

The first line will contain a message prompt to input the size of the array.

The succeeding lines will contain message prompts to input the elements of the array.

The next line will contain a message prompt to input the integer to be searched.

The last line contains the appropriate message.

Enter·the·size:·5
Element·#1:·3
Element·#2:·21
Element·#3:·2
Element·#4:·5
Element·#5:·23

Enter·the·integer·to·be·searched:·2
Present

Answer 1

#include <stdio.h>
#include <stdlib.h>


int main()
{
	int *arr;
	int i, size, n;
	bool found = false;

	printf("Enter the size: ");
	scanf("%d", &size);
	arr = (int*)malloc(size * sizeof(int));
	for (i = 0; i<size; i++)
	{
		printf("Element #%d: ", i + 1);
		scanf("%d", &arr[i]);
	}

	printf("Enter the integer to be searched:");
	scanf("%d", &n);
	for (i = 0; i < size; i++)
	{
		if (arr[i] == n)
			found = true;
	}
	if (found)
		printf("Present\n");
	else
		printf("None\n");

	free(arr);
	return 0;
}