What mass of nitrogen is needed to react with 21.25 g of hydrogen?
N2 + 3H2 = 2NH3
m(N2) = (m(H2)•Mr(N2)) / 3Mr(H2)
m(N2) = (21.25 g • 28 g/mol) / 3 • 2 g/mol = 99.17 g
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