Answer to Question #345942 in General Chemistry for Ennyl

Question

What is the pH of the solution containing 0.20 M NH3 and 0.15M NH4Cl?

Answer 1

K_b (NH₃)= 1.8*10^-5 and pK_b = 4.74

pOH = pK_b - log ([NH₄Cl] / [NH₃] )

pOH = 4.74 - log (0.15/0.2)

pOH = 4.74 - log 0.75

pOH = 4.74 + 0.12

pOH = 4.86

pH = 14 - pOH

pH = 14.00 - 4.86

pH = 9.14