A chemist performed this reaction and obtained 45.5 g BaSO4. How much HCI
was also produced?
Molar masses: 233.4 g/mol BaSO4,
36.5 g/mol HCI
A. 9.49 g HCI
C. 5.35 g HCI
B. 388 g HCI
D. 7.12 g HCI
Answer D: 7.12 g HCl
m (HCl) = m (BaSO4) / M (BaSO4) × M (HCl) = 45.5/233.4×36.5= 7.12 g
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