Answer to Question #349810 in General Chemistry for Gsgag

Question

To prevent dehydration, intravenous (IV) solution is given to hospital patients. Commonly used are solutions containing sodium chloride and glucose. A 150.0-mL IV solution contains 6.60 grams of glucose (CHO). What is the molarity of this solution? The molar mass of glucose is 180.16 g/mol.

Answer 1

Solution:

The molar mass of glucose (C₆H₁₂O₆) is 180.16 g/mol

Therefore,

Moles of glucose = (6.60 g C₆H₁₂O₆) × (1 mol C₆H₁₂O₆ / 180.16 g C₆H₁₂O₆) = 0.0366 mol C₆H₁₂O₆

Liters of solution = (150.0 mL) × (1 L / 1000 mL) = 0.150 L

Molarity = Moles of solute / Liters of solution

Therefore,

Molarity of the solution = (0.0366 mol) / (0.150 L) = 0.244 mol/L = 0.244 M

Molarity of the solution = 0.244 M

Answer: The molarity of the solution is 0.244 M