Answer to Question #221323 in Inorganic Chemistry for Mary

Question

A mineral contains 14.7% calcium and 67.5% tungsten the remainder is oxygen, find its Emperical formula

Answer 1

$Oxygen = 67.5-14.7= 52.8$

Moles

$calcium =\frac{14.7}{40.08}=0.367$

$tungsten =\frac{67}{183.84}=0.367$

$Oxygen =\frac{52.8}{32}=1.65$

Mole ratio

$Calcium =\frac {0.367}{0.367}=1$

$Tungsten =\frac {0.367}{0.367}=1$

$Oxygen =\frac {1.65}{0.367}=4.49= 4$

Empirical formula CaO4W