(MnO4-+) to MnO2(s)
The oxidizing agent is Mn and the element that gets reduced is O.
The half-cell oxidation reaction is
"Mn_2^+ + 2H_2O = MnO_2 +4H^+ + 2e"
and the half-cell reduction reaction is
"\\frac{1}{4} O_2 + H^+ + e = \u00bd H_2O."
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