A gas is initially at volume 40.0 L, pressure 600 mmHg and temperature 35 °C. Calculate the final pressure of the gas in atm if the volume and temperature are changed to 2500 mL and 225 K, respectively
Initial volume (V1) = 40 L ; pressure (P1) = 600 mmHg = 0.79 atm ;
Temperature (T1) = 35 + 273 K = 308 K
Final Volume (V2) = 2.5 L ; Temperature (T2) = 225 K ; Pressure of gas
P1V1"\/" T1 = P2V2"\/" T2
Substitute all values in above equation
(0.79) (40) "\/" (308) = (P2) (2.5) "\/" 225
Pressure of gas (P2) = 9.23 atm
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