Answer to Question #345318 in Inorganic Chemistry for Eyob

Question

how many ml of soln are required to prepare 0.02 mol of 2.5m Nacl soln?

Answer 1

C_M — concentration of molarity (mol/l) = 2,5 mol/l;

n — amount of substance (mol) = 0,02 mol

V — volume (litr).

V = n / C_M = 0,02 / 2,5 = 0,008 litr = 8 ml

ANSWER: 8 ml