if the O2 is reacting at the rate of 0.25 Ms-1,
calculate:
i. rate of NO2
Consider,
2NO(g)+O2(g)→2NO2(g)
Moreover, understand that reaction rates are proportional to the stoichiometry of the reaction. Hence,
"\\frac{0.070M}{S} \\times \\frac{2NO_2}{2NO}=\\frac{0.070M}{S}"
is the rate of appearance of nitrogen dioxide, and
"(0.070\\frac{M}{s})\\times \\frac{0_2}{2NO}=\\frac{-0.035 M}{s}"
is the rate of disappearance of the oxygen.
To be sure, reaction rates are merely,
"\\frac{\\bigtriangleup[A]}{\\bigtriangleup t}"
and the concentrations of the constituents are proportional to the stoichiometry.
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