1. How many moles of CO2 are produced according to equation (a) by the reaction of 6.0 mol of MgCO3?
Considering the equation which is already balanced:
MgCO
3
+2HCl→MgCl
2
+CO
2
+H
2
O ,
Limiting reagent here is HCl
Therefore, 6 moles of HCl will produce 3 moles of CO
2
Volume occupied by 3 moles =3×22.4=67.2
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