H2SO4 is dibasic acid so N\50 = 0.02N
Molarity of acid = 0.02\2 = 0.01M
So mol of acid = 10mL × 0.01M
= 0.1mmol
So amount of base = 2×0.1 mmol = 0.2mmol
Conc of base = (0.2×10-3 mol × 1000)\100
=2×10-3 M
POH = -log[OH-] = -log (2×10-3) =2.7
PH + POH = 14
PH = 14 -POH = 14 -2.7 = 11.3
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