In a binary liquid system, the excess molar volumes of species 1 and 2 at a constant temperature of 25ºC is represented by the following equation:
VE=x1x2[-1.026-0.220(x1-x2)] in cm3/mol
Given that the pure species molar volume V1 = 40.44 cm3/mol and V2 = 116.3 cm3/mol, you desire to form from 1000 cm3 of each pure species 1 and 2 a mixture at 25ºC.
1.  Calculate the mole fraction of species 1 in the mixture. (3)
Mole fraction=0.227
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