Answer to Question #284023 in Physical Chemistry for Harshraj

Question

Calculate the enthalpy change at 298 K for the cell reaction Zn ZnCI, (0-1 M), AgClis)|Ag

Given that E, is 0:8 V and at 298 K is - 4-0 x 10+ VK-

Answer 1

Enthalpy change =−42.0 kJ mol−1