Calculate the enthalpy change at 298 K for the cell reaction Zn ZnCI, (0-1 M), AgClis)|Ag
Given that E, is 0:8 V and at 298 K is - 4-0 x 10+ VK-
Enthalpy change =−42.0 kJ mol−1
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment