A steel cylinder has a volume of 25.0 L and is filled with N2 gas to a pressure of 200 atm. @ 30.0°C. How many moles of N2 gas does the cylinder contain?Â
30.0oC = 273.15 + 30.0 = 303.15 K
"n=\\frac{PV}{RT}=\\frac{200\\ atm\\times25.0\\ L}{0.08206\\frac{L\\cdot{atm}}{mol\\cdot{K}}\\times303.15\\ K}=201\\ mol"
Answer: 201 mol
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