Answer to Question #323339 in Physical Chemistry for Elydon

Question

Two mole of an ideal gas is heated at a constant pressure of 101.3K Nm^-2 from 273.2 K to 373K. Calculate, in Joules, the work involved

Answer 1

n = 2 mol;

R = 8.314 J/(K*mol);

P = 101.3 K/nm²;

T₁ = 273.2 K;

T₂ = 373 K;

W = n * R * $\Delta$ T = n * R * (T₂ - T₁) = 2 * 8.314 * (373 - 273.2) = 2 * 8.314 * 99.8 = 1659 J = 1.659 kJ.

Answer: 1.659 kJ.