If the empirical formula of a compound is P2O3, and it has a molecular weight equal to 220 g/mol, what is its molecular formula?
Solution:
Empirical formula = P2O3
Molar mass of P2O3 = 2×Ar(P) + 3×Ar(O) = 2×31 + 3×16 = 110 (g/mol)
Molecular formula = (P2O3)n
Molar mass of (P2O3)n is 220 g/mol
n = (Molecular formula / Empirical formula) = (Molar mass of (P2O3)n / Molar mass of P2O3)
n = 220 / 110 = 2
Therefore,
Molecular formula = (P2O3)2 = P4O6
Answer: The molecular formula of a compound is P4O6
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