Answer to Question #315407 in Chemistry for sael

Question

Determine the volume occupied by 4.26 g of CO2 gas at STP. Use the equation: V= nRTP

Answer 1

Solution:

STP = Standard Temperature and Pressure (T = 273.15 K and P = 1 atm)

R = universal gas constant = 0.0821 L atm K⁻¹ mol⁻¹

The molar mass of CO₂ is 44.01 g/mol

Therefore,

Moles of CO₂ = (4.26 g CO₂) × (1 mol CO₂ / 44.01 g CO₂) = 0.0968 mol CO₂

n(CO₂) = 0.0968 mol

Ideal gas law can be used:

PV = nRT

To find the volume, solve the equation for V:

V = nRT / P

V = (0.0968 mol × 0.0821 L atm K⁻¹ mol⁻¹ × 273.15 K) / (1 atm) = 2.17 L

V = 2.17 L

Answer: The volume of CO₂ is 2.17 L