Answer to Question #327799 in Chemistry for nicole

Question

 A 10.00‐g sample containing an analyte is transferred to a 250‐mL volumetric flask              and diluted to volume. When a 10.00 mL aliquot of the resulting solution is diluted                 to 25.00 mL it gives signal of 0.235 (arbitrary units). A second 10.00‐mL portion of                the solution is spiked with 10.00 mL of a 1.00‐ppm standard solution of the analyte             and diluted to 25.00 mL. The signal for the spiked sample is 0.502.  (a) Calculate the weight percent (%w/w) of analyte in the original sample.                        (7) (b) What calibration method was used here? Explain your answer. 

Answer 1

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