Answer to Question #334157 in Chemistry for shimmy

Question

2.   A tank ( not rigid) contains 2.5 litres of helium gas at 28⁰C . At constant pressure, what will be the volume of the tank after heating it and its content to 43⁰C temperature?

Answer 1

V₁ = 2.5 L

T₁ = 28°C + 273.15 = 301.15 K

P₁ = P₂ = constant

V₂ = ???

T₂ = 43°C + 273.15 = 316.15 K

Solution:

Since the pressure and amount of gas remain unchanged, Charles's law can be used.

Charles's law can be expressed as: V₁ / T₁ = V₂ / T₂

V₁T₂ = V₂T₁

To find the volume, solve the equation for V₂:

V₂ = V₁T₂ / T₁

V₂ = (2.5 L × 316.15 K) / (301.15 K) = 2.6245 L = 2.6 L

V₂ = 2.6 L

Answer: The volume of the tank will be 2.6 liters