Answer to Question #337123 in Chemistry for ash

Question

What is the pH of an aqueous solution of 3.99×10^-2 M nitric acid? 

pH = 

Answer 1

Solution:

nitric acid = HNO₃

HNO₃ is a strong acid because it dissociates almost completely.

HNO₃(aq) = H⁺(aq) + NO₃⁻(aq)

Therefore,

[H⁺] = C(HNO₃) = 3.99×10⁻² M

We can convert between [H⁺] and pH using the following equations:

pH = −log[H⁺]

pH = −log(3.99×10⁻²) = 1.399 = 1.4

pH = 1.4

Answer: pH = 1.4