how many grams would be contained in 3.49 x 10^80 molecules of H2SO4?
Solution:
One mole of any substance contains 6.02×1023 atoms/molecules.
Therefore,
Moles of H2SO4 = (3.49×1080 molecules) × (1 mol / 6.02×1023 molecules) = 5.797×1056 mol H2SO4
The molar mass of H2SO4 is 98.079 g/mol
Therefore,
Mass of H2SO4 = (5.797×1056 mol H2SO4) × (98.079 g H2SO4 / 1 mol H2SO4) = 5.686×1058 g H2SO4
Mass of H2SO4 = 5.686×1058 g
Answer: 5.686×1058 grams of H2SO4
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