A man wishes to have an amount of P2,769.84 after 5 years. He deposited P500 each year into a savings bank that pay “r” percent per annum compounded continuously. Compute the value of “r”.
Continuous compounding is given as;
"P(t)=P_oe^{rt}"
where
"P(t)=2769.84"
"P_o=500"
"t=5"
to find the value of r, we replace the known variables to the equation as follows;
"2769.84=500e^{5r}"
dividing by 500 on both sides of the equation;
"5.53968=e^{5r}"
equivalent to;
"e^{5r}=\\frac{34623}{6250}"
we take the natural logs from both sides to eliminate e
"5rlne=ln34623-ln6250"
"r=\\frac{ln34623-ln6250}{5}"
substituting the values of "ln" and dividing by 5 we get;
"r=0.34"
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