Let Q be the amount of sait in the tank and "dt\/dQ"
be the rate of change of amount in the tank
We get the equation as
"\\space dt\/\ndQ\n\u200b\t\n + \n1\/20\n\n\u200b\t\n Q=0"
It is linear equation and the solution of it is "Q=Ce ^{-\\frac{t}{20}\nt}\n\u200b"
At t=0 , the value of Q is 20
"\u21d2C=20"
Therefore the equation is"\\space Q=Ce ^{-\\frac{t}{20}\nt}"
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