A beam AB of length 1 m is supported horizontally at A and B. A weight of 500 N is attached on the rod at C. If the support at A can not bear a pressure more than 300 N, find the distance of C from A, when the support A is about to fail.
Thus the distance of C from A is 40 cm
Explanation:
We are given that:
Solution:
Let distance of C from A = x,
so distance from B = 1 - x
Balancing torque at point B
500 (1-x) = 300( 1)
x = 2/5 m
x = 40 cm
Thus the distance of C from A is 40 cm.
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