Find the area under the curve y=x^2 + 1 and the x-axis between x=0 and x=3. *
"\\mathrm{The\\:area\\:under\\:a\\:curve\\:is\\:the\\:area\\:between\\:a\\:curve}\\:f\\left(x\\right)\\:\\mathrm{and\\:the\\:x-axis\\:on\\:an\\:interval}\\:\\left[a,\\:b\\right]\\:\\mathrm{given\\:by}\\\\\nA=\\int _a^b|f\\left(x\\right)|dx\\\\\n=\\int _0^3\\left|x^2+1\\right|dx\\\\\n=12"
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