Answer to Question #266563 in Civil and Environmental Engineering for CRIS

Question

 Water flows at a depth of 40 cm in a100-cm-diameter storm sewer. Calculate the flow rate and the mass flux if the average velocity is 3m/s.

Answer 1

Given:

d= 100 cm = 1m

v=1m/s

solution:

$A= \pi/4 (d)^2$

$A= 3.14/4(1)^2 = 0.7854m^2$

flow rate

$Q=AV= 0.7854\times 3= 2.356 m^3/s$

mass flux

$M_f= Q\rho= 2.356\times1000kg/m^3$

$M_f= 2356 kg/s$