Use differentials to approximate the volume of material needed to make a rubber ball if the radius of the hollow inner core is 2 in., and the thickness of the rubber is 1/8 in.
"t=2 \\space in"
"\\sigma_c=500 Mpa"
"\\tau=200 Mpa"
Solution:
as we know that
"\\sigma_c\\times A_c = \\tau\\times A_s"
"\\sigma_c\\times\\pi\/4 D^2=\\tau\\times\\pi D t"
"500\/4 (D)= 200\\times 10"
"D= 16 mm"
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