Answer to Question #319487 in Civil and Environmental Engineering for joe

Question

A +4% grade line intersects a -2 % grade line at station 6+800, where the elevation is 642.40 m. as shown in the figure. Determine the elevations of 100-m stations for this 1,000-m unequal tangent curve

Answer 1

From the Table , K = 181

L = KA = 642.40 (4-(-2)) = - -5139.20

Station of BVC = (1000 - 100) = 900

Elevation at any station on the leading tangent can be found in a similar manner.

The elevation on the curve can be found by adding the elevation on the leading tangent to the offset, which can be found using the equation;

$Y=\frac{A}{200L}x^2$

The question is incomplete since there is no figure being referred to.

Thank you