a shaft manufacturer has produced 500 ms pipes of nominal outside diameter of 150mm. measurement show the maximum diameter to be 151.1mm while minimum diameter to be 149.3mm. hoever during shipment pipes of diameter 150+-0.5mm were accepted and the rest were rejected.assume gaussian/normal distribution.
N=500
D=150mm
Di=149.3mm
Do=151.1mm
Df=150+-0.5mm
∆=(151.1-149.3)+-0.5
=1.8+-0.5
=1.3 or 2.3
Comments
Leave a comment