If log4 5=a and log5 6=b, then log3 2 is equal to
"a\\cdot b=\\log_45\\cdot \\log_56=\\log_46=\\frac{1}{2}\\log_26=\\frac{1}{2}(\\log_23+\\log_22)=\\frac{1}{2}(\\log_23+1)"
"2ab=\\log_23+1"
"\\log_23=2ab-1"
"\\log_3 2=\\frac{1}{\\log_2 3}=\\frac{1}{2ab-1}"
Answer: "\\log_32=\\frac{1}{2ab-1}" .
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