Answer to Question #287451 in Algebra for austyn

Question

The first aircraft has 54 more seats than the second aircraft. The third aircraft has 58 fewer seats than the second aircraft. If their total number of seats is 389. find the number of seats for each aircraft.

(Simplify your​ answer.)

Answer 1

Let A be :1st aircraft

B be : 2nd aircraft

C be 3rd aircraft

A = $54 + x$

B = $x$

C = $x - 58$

$54+x+x+x-58=389$

$x=131$

Number of seat in aircraft:

A =185

B=131

C=73