Answer to Question #298479 in Algebra for yusuph

Question

find the value of x,

x²+2x+1=0

Answer 1

Solution;

$x^2+2x+1=0$

Rewrite as;

$x^2+x+x+1=0$

$x(x+1)+1(x+1)=0$

$(x+1)(x+1)=0$

Therefore;

$x=-1$