Answer to Question #309110 in Algebra for Carl Johnson

Question #309110

(3a-5)(9a2+25)(3a+5)

Expert's answer

Multiply 3a-5 by 3a+5

Apply this law: (a+b)(a-b)=( a²-b²)

(3a+5)(3a-5)=(9a²-25)

Then multiply (9a²-25) by (9a²+25) applying the above law.

(9a²-25)(9a²+25)=(81a⁴-625)

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