(i) 𝑦= 2𝑥2 + 12𝑥 + 18
Let y = 0
2x² +12x + 18= 0
0 = 2x² + 12x + 18
0 = x² + 6x +9
0 = x² + 3x + 3x +9
0 = x(x+3) + 3(x+3)
0 = (x+3)(x+3)
x+3 =0
x = -3
Therefore, y= 0, x = -3
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